Hackerrank | 10 Days of Javascript | Day 6-Solution in JS | Bitwise-Operators-Hackerrank-Solution-in-JS
Objective
Today, we're practicing bitwise operations. Check the attached tutorial for more details.
Task
We define to be a sequence of distinct sequential integers from to ; in other words, . We want to know the maximum bitwise AND value of any two integers, and (where ), in sequence that is also less than a given integer, .
Complete the function in the editor so that given and , it returns the maximum .
Note: The symbol represents the bitwise AND operator.
Input Format
The first line contains an integer, , denoting the number of function calls.
Each of the subsequent lines defines a dataset for a function call in the form of two space-separated integers describing the respective values of and .
Constraints
Output Format
Return the maximum possible value of for any in sequence .
Sample Input 0
3
5 2
8 5
2 2
Sample Output 0
1
4
0
Explanation 0
We perform the following function calls:
When and , we have the following possible and values in set :
The maximum of any that is also is , so we return .
- When and , the maximum of any in set is (see table above), so we return .
- When and , the maximum of any in set is (see table above), so we return .
Sample Input 1
2
9 2
8 3
Sample Output 1
1
2
Explanation 1
We perform the following function calls:
- When and , the maximum of any in set is (see table above), so we return .
- When and , the maximum of any in set is (see table above), so we return .
https://www.hackerrank.com/challenges/js10-bitwise/problem
Day 6: Bitwise Operators Solution in JS'use strict'; process.stdin.resume(); process.stdin.setEncoding('utf-8'); let inputString = ''; let currentLine = 0; process.stdin.on('data', inputStdin => { inputString += inputStdin; }); process.stdin.on('end', _ => { inputString = inputString.trim().split('\n').map(string => { return string.trim(); }); main(); }); function readLine() { return inputString[currentLine++]; } function getMaxLessThanK(n, k) { let largest = 0; let current = 0; for (let i = 1; i < n; i++) { for (let x = i + 1; x <= n; x++) { current = i & x; if (current < k && current < n && current > largest) { largest = current; } } } return largest; } function main() { const q = +(readLine()); for (let i = 0; i < q; i++) { const [n, k] = readLine().split(' ').map(Number); console.log(getMaxLessThanK(n, k)); } }
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